(y^2+1)(y-4)=0

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Solution for (y^2+1)(y-4)=0 equation: 


Simplifying
(y2 + 1)(y + -4) = 0

Reorder the terms:
(1 + y2)(y + -4) = 0

Reorder the terms:
(1 + y2)(-4 + y) = 0

Multiply (1 + y2) * (-4 + y)
(1(-4 + y) + y2(-4 + y)) = 0
((-4 * 1 + y * 1) + y2(-4 + y)) = 0
((-4 + 1y) + y2(-4 + y)) = 0
(-4 + 1y + (-4 * y2 + y * y2)) = 0
(-4 + 1y + (-4y2 + y3)) = 0
(-4 + 1y + -4y2 + y3) = 0

Solving
-4 + 1y + -4y2 + y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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